Question

Please..........
Solve the problem .

Answer 1

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Here, we have,
(BC) ^2 = AC * CD.
Or, BC * BC = AC * CD.
Or, AC/BC = BC/CD.

Now,.. We clearly can say that,
angle ACB = angle BCD.

Thus, triangle ABC is similar to triangle BCD, by SAS axiom of similar triangles.

Thus, we get that in similar triangles the ratio of sides is equal.
So, AB/AC = BD/BC

But it is given that AB = AC.

Thus, BD/BC = 1.
So, BD = BC

Hence proved,.

Hope this helps,.

If helps, please mark it as brainliest ^_^

Answer 2

hey mates your answer is here

Here, we have,

(BC) ^2 = AC * CD.

Or, BC * BC = AC * CD.

Or, AC/BC = BC/CD.

Now,.. We clearly can say that,

angle ACB = angle BCD.

Thus, triangle ABC is similar to triangle BCD, by SAS axiom of similar triangles.

Thus, we get that in similar triangles the ratio of sides is equal.

So, AB/AC = BD/BC

But it is given that AB = AC.

Thus, BD/BC = 1.

So, BD = BC

Hence proved,.

may be it's helpful for you

please mark me as brainliest ✌️