Question

please solve the problem ​

Answer 1

$\huge{\mathfrak{Solution:-}}$

Given:-

Volume of solute = 2 ml

Volume of solvent = 45 ml

So,

Volume of solution = volume of solute + volume of solvent

                                 = 2 ml + 45 ml

                                 = 47 ml

$\bold{Volume\;by\;volume\;percentage = \frac{Volume\;of\;solute}{volume\;of\;solution}\times 100}$

$\bold{= \frac{2\times 100}{45}}\\ \\ \\ \bold{= 4.44\;\%}$

$\boxed{\bold{4.44\;\%\;(Answer)}}$

Answer 2

ANSWER

Given,

Volume of Acetone

i.e Volume of solute =2ml

Volume of aqueous Solution

i.e Volume of Solvent = 45 ml

Now we know =>

Percentage of Concentration of solute of a solution is given by=>

$\dfrac{Volume of Solute}{Volume of Solvent}$ ×100

=>$\dfrac{2}{45}$ ×100

=> $\dfrac{200}{45}$

=>4.4 %

Hence the percentage of Acetone in the aqueous Solution is 4.4% by volume.

Remember

1)Concentration of any substance gives the power or strength of the substance in an solution or mixture.

2)To find concentration, we have several methords.

A) Mass by Mass concentration =>

$\dfrac{Mass of Solute}{Mass of Solvent}$ ×100

B) Volume by Volume concentration =>

$\dfrac{Volume of Solute}{Volume of Solvent}$ ×100