please solve the problem as early as possible
Answers
Answer:
Given
Number of observations =50
Class interval frequency
0-10. 4
10-20 4
20-30 f1
30-40 10
40-50 f2
50-60 8
60-70 5
As we know sum of frequency = number of observations
4+4+f1+10+f2+8+5
f1+f2+31=50
f1+f2=50-31
f1+f2=19. - - - - - - - - (1)
Now
Class interval frequency
5 4
15 4
25 f1
35 10
45 f2
55 8
65 5
(20+60+25f1+350+45f2+440+325) /50 =38.2
25f1+45f2+1195=38.2x50
25f1+45f2+1195=1910
25f1+45f2=1910-1195
25f1+45f2=715
Taking 5 common out
5(5f1+9f2) =715
5f1+9f2=715/5
5f1+9f2=143. - - - - - - - - (2)
So here we have two unknown variables and two equations
So now we can simply find out the value of 2 unknown values f1 and f2
Equation 1->. f1+f2=19
Equation 2->. 5f1+9f2=143
From equation 1 we get
f1= 19-f2. - - - - - - - (3)
Niw putting the value of f1 in equation 2 we get,
5(19-f2)+9f2=143
95-5f2+9f2=143
95+4f2=143
4f2=143-95
4f2=48
f2=48/4
f2=12
Now putting the value of f2 in equation 3 we get,
f1=19-12
f1=7
So our answer is f1=7,f2=12
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