please solve the problem faster
class 10th maths triangles chapter question
given is
DE is parallel to BC
then prove that AD/AB = AE/AC
please solve fast then i will marks you as brainlist
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I hope you understand and pls mark me as brain list
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9GULSHAN1:
i also never follow you
thanks
Good night and sweet dreams
I don't need you and your help OK now don't disturb me
you also don't disturb me
go to bed
Listen mr sheoran prateek... In class 10 th. The examinors will not check long stories.. They check your smartness
oh but they don't gave full marks in short tricks ok
And yes, that ans is not a short cut to that question. In maths marks are not given to long stories, but to that person who have answered the question in a very prominent and smart way
They are not short tricks... U r personality is very short..
Answered by
1
Hii mate here is your ans
Given: DE parallel to BC
RTP: AD÷AB = AE÷AC
PROOF
In triangle ABC and triangle ADE
DE IS PARALLEL TO BC
ANGLE ADE =ANGLE ABC (corresponding angles)
ANGLE DAE = ANGLE BAC ( common)
BY A. A criteria
ADE ~ ABC
As the triangles are similar their sides are proportional
AD/AB=DE/BC=AE/AC
From above eq. We get
AD/AB = AE/AC
(Hence proved)
Hope, it will help you
Given: DE parallel to BC
RTP: AD÷AB = AE÷AC
PROOF
In triangle ABC and triangle ADE
DE IS PARALLEL TO BC
ANGLE ADE =ANGLE ABC (corresponding angles)
ANGLE DAE = ANGLE BAC ( common)
BY A. A criteria
ADE ~ ABC
As the triangles are similar their sides are proportional
AD/AB=DE/BC=AE/AC
From above eq. We get
AD/AB = AE/AC
(Hence proved)
Hope, it will help you
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