Question

please solve the problem is math

Answer 1

Answer-
$\frac{ 9 {x}^{2} + 4 + 12x + 3 }{3x + 2} = - 4 \\ 9 {x}^{2} + 12x + 7 = - 4(3x + 2) \\ 9 {x}^{2} + 12x + 7 = - 12x - 8 \\ 9 {x}^{2} = - 24x - 15 \\ 3(3 {x}^{2} ) = 3( - 8x + - 5) \\ 3 {x}^{2} = - 8x - 5 \\ 3 {x}^{2} + 8x + 5 = 0 \\ 3 {x}^{2} + 3x + 5x + 5 = 0 \\ 3x(x + 1) + 5(x + 1) = 0 \\ (3x + 5)(x + 1) = 0 \\ so \: either \: (3x + 5) \: is \: zero \: or \: (x + 1) \: is \: zero \\ so \: either \: x = \frac{ - 5}{3} \: or \: x = - 1$
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