Question

please solve the problem kl mera exam h​

Answer 1

Step-by-step explanation:

let p:q= 11x,19x

in∆ABC

P+Q+90=180( BY angle sum property)

11x+19x=90

30x=90

x=3°

angle p=11*3=33

angle q=19*3=57

AB||CE,AC IS TRANSVERSAL

P=angle ACE

angleACE=33°

in ∆ACE

angle ACE+32=r(exterior angle property)

32+33=r

65°=r.

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