Question

please solve the problem there are two questions in it

Answer 1

2). ( x+3) (x-1) =3(x-1/3)
=x(x-1)+3(x-1) =3x - (1*3/3)
=x²-x +3x-3=3x-1
=x²-x+3x-3-3x+1=0
=x²-x-2=0
=x²-2x+x-2=0
=x(x-2) +1(x-2) =0
(x+1) (x-2)
x+1=0
x=-1
x-2=0
x=2
roots of quadratic equation are -1, 2

3).. (2x²/5) -x -(3/5)=0
=(2x²-5x-3) /5 =0
=2x²-5x-3 =0*5
=2x²-6x+x-3 =0
=2x(x-3) +1(x-3) =0
=(2x+1) (x-3)
2x+1=0
2x=-1
x=-1/2
x-3=0
x=3
Roots are -1/2and 3