Math, asked by rohin111bhattacharya, 9 months ago

please solve the problem. wrong answer will be reported ​

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Answered by mysticd
1

 Given \: \alpha + \beta = 90\degree \: -- (1)

 \implies \beta = 90\degree - \alpha \: --(2)

 LHS = \red{ \frac{cos^{2} \alpha + cos^{2} \beta }{ sin^{2} ( \alpha + \beta ) } } \\= \frac{cos^{2} \alpha + cos^{2} (90 - \alpha) }{ sin^{2} 90\degree }  \: [ From \: (1) \:and \:(2) ]

 = \frac{ cos^{2} \alpha + sin^{2} \alpha }{1}

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We know that,

 1. sin 90\degree = 1 \\2. cos^{2} \alpha + sin^{2} \alpha = 1

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 \green {= 1 } \\= RHS

 Hence \:proved

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