Question

please solve the problem. wrong answer will be reported ​

Answer 1

$LHS = \red{ \frac{tan 57\degree + cot 37 \degree }{ tan 37\degree + cot 53 \degree }}$

$= \frac{tan 57\degree + cot (90- 53) \degree }{ tan (90-53)\degree + cot 53 \degree }\\= \frac{tan 57\degree + tan 53 \degree }{ cot 53\degree + cot 53 \degree } \\= \frac{\cancel {2}tan 57 \degree }{\cancel { 2}cot 53 \degree } \\= tan 57 \degree tan 53 \degree \\= tan 57 \degree tan (90 - 37) \degree \\= tan 57 \degree cot 37 \degree \\= RHS$

♪••.

Answer 2

Answer:

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