Question

please solve the ques in the image
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Answer 1

Step-by-step explanation:

Since, a

3

+b

3

+c

3

−3abc=(a+b+c)(a

2

+b

2

+c

2

−bc−ca−ab)

Given, a+b+c=0

∴a

3

+b

3

+c

3

−3abc=0

∴a

3

+b

3

+c

3

=3abc