Please solve the question 1 and 2. plzz urgent h
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Total distance 40m in 40 sec.
Total time taken by the farmer = 2 min
20 sec. =140 seconds.
Total rounds completed=
140/40=3.5 rounds
That means if the farmer starts from
point A of the square field, he
reaches point C.
Therefore, displacement is AC.
Assume ABC is a right angled triangle.
Therefore,
AC2= AB2 +BC2
AC2= (10)2 +(10)2
AC2= 100+100
AC2=200
AC = (200)1/2
AC= 10× (2)½
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Total time taken by the farmer = 2 min
20 sec. =140 seconds.
Total rounds completed=
140/40=3.5 rounds
That means if the farmer starts from
point A of the square field, he
reaches point C.
Therefore, displacement is AC.
Assume ABC is a right angled triangle.
Therefore,
AC2= AB2 +BC2
AC2= (10)2 +(10)2
AC2= 100+100
AC2=200
AC = (200)1/2
AC= 10× (2)½
hope it help
mark as brainlist
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