Math, asked by singhquitaryan, 1 year ago

please solve the question​

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Answers

Answered by sivahemanth71
0

Step-by-step explanation:

let theta beα

sinα=c/√c^2+d^2

sin^2α=c^2/c^2+d^2

1-cos^2α=c^2/c^2+d^2

cos^2(α)=1-c^2/c^2+d^2

cos^2(α)=c^2+d^2-c^2/c^2+d^2

cos^2(α)=d^2/c^2+d^2

cos(α)=d/√c^2+d^2

tanα=sinα/cosα

=c/√c^2+d^2/d/√c^2+d^2

=c/d

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