Question

please solve the question​

Answer 1

Answer:-

Explanation:-

Given:-

a CosA + b SinA = m........(i)

a SinA - b CosA = n..........(ii)

Answer:-

m = a CosA + b SinA = m

Square both side in equation (i)

m² = (a CosA + b SinA)²

m² = a² Cos²A + b Sin²A + 2a CosA * b SinA...........(iii)

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n = a SinA - b CosA

Square both side in equation (ii)

n² = (a SinA - b CosA)²

n² = a² Cos²A + b² Sin²A - 2a CosA * b SinA..........(iv)

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Add equation (iii) and (iv)

m² + n² = a² Sin²A + b² Cos²A + a² Cos²A + b² Sin²A

[ 2a CosA * b SinA and - 2 CosA * b SinA are canceled while addition]

We know that Sin²A + Cos²A = 1

m² + n² = a² + b²

So,the value is a² + b²

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Same question answered by me :-

https://brainly.in/question/11590712

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Answer 2

Step-by-step explanation:

m² by using (a+b)²= a²+b²+2ab

n² by using (a-b)²= a²+b²-2ab