Math, asked by aayaankumar1, 11 months ago

Please solve the question​

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Answered by abcdefghijklmn82
1

Answer:

ABCD is a rhombus

AC is a diagonal =36cm

BD is another diagonal=?

diagonal AC and BD intersect each other at O

since we know that diagonals of a rhombus bisect each other at 90°

so,<AOB=90° and AO=18cm

which means ∆AOB is a right angle triangle

In ∆AOB

AB square = AO square +OB square

900=324+OB square

OB square =900-324

OB =√576

OB=24

BD=OB ×2(since diagonal of a rhombus bisect each other)

BD=24×2

BD=48cm

The another diagonal = 48cm

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