Question

please solve the question​

Answer 1

Answer:

4) 10

Step-by-step explanation:

please refer the diagram given.

calculating components, we get that

$\cos(30) = \frac{mg}{component \: of \: mg \: antiparallel \: to \: n} \\ hence \\ component \: of \: mg = mg \sec(30) = \frac{ \sqrt{3} }{2} (10) \frac{2}{ \sqrt{3} } = 10$

Answer 2

Answer:

5

Step-by-step explanation:

the diameter of the hemispherical shell is

2R

The rod is R In length

so it lies horizontally within the shell

the reaction force always acts perpendicular to the surface of contact

2Nsin(theta) = mg

N = mg/2*sin(theta)

N = 5√3/2*√3/2

N = 5