please solve the question...!!!
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Answer:
180-55
=125
Bpq=30
90+55 =145
180-145=35
Pba=35
Answered by
1
Step-by-step explanation:
basically a chord passing through centre and subtended an angle on any point of circle is 90 degrees
so angle BRA IS 90 therefore in triangle BAR remaining angle is 40 so angle BAR is 40
it is also a Cyclic quadrilateral so. sum of opp sides is 180 so PAR +PBR =180
SO PAB+BAR+PBA+ABR=180
SO 55+40+PBA+50=180
PBA=35
therefore APB =90
SO IN ABQP OPP SIDES =180
SO ABQ +QPA=180
SO 60+BPQ+BPA=180
SO 60+BPQ+90=180
BPQ=30
SO FINALLY ANGLES PBA=35,BPQ=30,BAR=40
I THINK IT MAY HELP U BETTER
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