Question

please solve the question​

Answer 1

Step-by-step explanation:

Let

1st digit=x (100's place)

3rd digit=y (1's place)

Given

2nd digit=0 (10's place)

x+y=10. =>eq1

number=100(x)+10(0)+1(y)

=100x+y

number obtained by reversing digits=100(y)+10(0)+1(x)

=100y+x

But,

100y+x-(100x+y)=396

99y-99x=396

y-x=396/99=4. =>eq2

eq1+eq2

x+y+y-x=10+4

2y=14

y=7

from eq1

x=3

number is 307