Question

please solve the question ​

Answer 1

Answer:

Step-by-step explanation:

ANSWER:-

Before attempting the Question ,

we need to know the Quadratic Formula in which the whole question is Based.

Quadratic Formula:

$x = \frac{-b\ \pm\ \sqrt{b^2-4ac}}{2a}$

Discriminant Formula:-

$D=b^2-4ac$

$\boxed{1)\ 2x^2+x-1}$

$D = (1)^2-4(2)(-1)\\= 1+8\\= 9$

$\boxed{2)\ x^2-4x+4}$

$D = (-4)^2-4(1)(4)\\= 16-16\\=0$

$\boxed{3)\ x^2+x+1}$

$D = (1)^2-4(1)(1)\\= 1-4\\= -3$

$\boxed{4)\ 4x^2-4x+1}$

$D = (-4)^2-4(4)(1)\\= 16-16\\=0$

1. Roots are real and unequal(D>0)
2. Roots are real and Equal(D=0)
3. Roots are unequal and not equal(D<0)
4. Roots are real and Equal (D=0)