please solve the question
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given,as per given in question and imaginary triangle made in my uploaded figure( look the pic i uploaded),
A1=Area of rectangle( including traingle)
A2=Area of traingle
lenght of rectangle (L1)= 6 cm
breadth of rectangle(B1)= 3 cm
breadth of traingle(B2)= 1 cm
height of traingle(h2)=1cm
Step-by-step explanation:
A1=L1*B1=6cm*3cm=18cm^2
A2=1/2*B2*h2=1/2*1*1=0.5cm^2
the area of figure is =A1-A2=18cm^2-0.5cm^2=17.5cm^2
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