please solve the question
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hope so it will help you
class interval and frequency will be same I'm just writing the cf. hope you will understand ☺
cf
4
9
22
42
56
64
68
then median formula
= l+{n/2 +cf} × h
÷
f
now put the values
= 125 + {34-22÷20} × 20
=125 + {12÷20} × 20
(20 will be cancelled )
=125+{12}
=137
therefore , 137 is the median
class interval and frequency will be same I'm just writing the cf. hope you will understand ☺
cf
4
9
22
42
56
64
68
then median formula
= l+{n/2 +cf} × h
÷
f
now put the values
= 125 + {34-22÷20} × 20
=125 + {12÷20} × 20
(20 will be cancelled )
=125+{12}
=137
therefore , 137 is the median
Missmk:
is this is correct answer ?
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