Question

please solve the question
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Answer 1

Solution:-

$\rm \implies \: \dfrac{ {x}^{2} }{ {x}^{2} + 1} + \dfrac{ {x}^{2} - 5}{ {x}^{2} - 6} = 2$

By taking lcm we get

$\rm \implies \: \dfrac{ {x}^{2}( {x}^{2} - 6) + ({x}^{2} - 5) ( {x}^{2} + 1)}{ ({x}^{2} + 1)( {x}^{2} - 6) } = 2$

$\rm \implies \dfrac{ {x}^{4} - 6 {x}^{2} + {x}^{4} - 5 {x}^{2} + {x}^{2} - 5 } { {x}^{4} - 6 {x}^{2} + {x}^{2} - 6 } = 2$

$\rm \implies \: \dfrac{2 {x}^{4} - 10{x}^{2} - 5}{ {x}^{4} - 5 {x}^{2} - 6 } = 2$

$\rm \implies \: 2 {x}^{4} - 10 {x}^{2} - 5 = 2( {x}^{4} - 5 {x}^{2} - 6)$

$\rm \implies \: 2 {x}^{4} - 10 {x}^{2} - 5 = 2 {x}^{4} - 10 {x}^{2} - 12$

$\rm \implies \: \cancel{ 2 {x}^{4}} - \cancel{10 {x}^{2}}- 5 = \cancel{2 {x}^{4} } - \cancel{10 {x}^{2} } - 12$

$\rm \implies \: 0 - 5 = 12$

This equation is not defined because tha value of x is not coming

An equation for a straight line is called a linear equation. The general representation of the straight-line equation is y=mx+b, where m is the slope of the line and b is the y-intercept.

Linear equations are those equations that are of the first order. These equations are defined for lines in the coordinate system.