please solve the question. ..
Answers
Answer:
100000
Step-by-step explanation:
Given cost price of land = 3,60,000.
(i)
Given, overall profit = 10%.
Selling price of the whole part = CP * (100 + gain%)/100
= 360000 * (100 + 10)/100
= 3600 * 110
= 396000.
(i)
Cost price of (1/3)rd of plot = (1/3) * 360000
= 120000.
Loss incurred = 20%.
We know that Selling price = {(100 - Loss%/100} * Cost price
= {(100 - 20/100} * 120000
= (80/100) * 120000
= 96000.
(ii)
Given that (2/3)rd of the plot left at the profit of 25%.
⇒ (2/3) * (1 - 1/3)
⇒ (2/3) * (2/3)
⇒ 4/9 part of initial area.
So,cost price of (4/9) part of initial area = 360000 * (4/9)
= 160000
Selling price = CP * {(100 + Gain%)/100}
= 160000[100 + 25/100]
= 160000[125/100]
= 200000
(iii)
Cost price of plot left = 360000 * (1 - 1/3 * 4/9)
= 80000
(iv)
⇒ Selling price of remaining land = 390000 - (200000 + 96000)
= 396000 - 296000
= 100000.
Hope it helps!
Answer:
100000
Step-by-step explanation:
Cost of plot = Rs 3,60,000 (C)
Target sale value to achieve 10% profit on the whole plot = 360000 + (360000 x 0.1) = Rs 396000 (T)
Cost of 1/3 plot = 360000 ÷ 3 = Rs 120000 (c1)
Cost of 2/3 plot = 360000 - 120000 = Rs 240000
Cost of 2/3 plot of 2/3 (plot left after selling 1/3 plot) = 240000 x (2 ÷ 3) = Rs 160000 (c2)
20% loss amount on sale of 1/3 plot = 120000 x 0.2 = Rs 24000
Sale price of 1/3 plot = a - 24000 = Rs 96000 (s1)
Remaining plot is 2/3
Man sells 2/3 of this 2/3 plot at a profit of 25% = 160000 x 0.25 = Rs 40000
Sale price of 2/3 of 2/3 plot = 160000 + 40000 = Rs 200000 (s2)
Total sale value realized so far R = s1 + s2 = 96000 + 200000 = Rs 296000
Target sale value to achieve 10% profit on the whole plot = S (calculated above)
∴ Required sale price for the remaining plot = S - R
= 396000 - 296000
= Rs 100000