Question

please solve the question​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

given equation is x^2-2px+8p-15=0

if it has equal root

then we know b^2-4ac= 0

put value s

(-2p)^2-4×1×(8p-15)=0

4p^2 =4 (8p-15)

p^2=8p-15

p^2-8p+15=0

p^2-5p-3p+15=0

p (p-5)-3 (p-5)=0

(p-5)(p-3)=0

therefore p =5 or p=3