Question

please solve the question and give me its solution

Answer 1

HERE IS YOUR ANSWER MATE!!!!!!

SEE BELOW:---

Distance of segment dividing the line internally and externally in same rato will be equal to the length of line.

Now the distance of line

=√(x2-x1)^2+(y2-y1)^2

=√(5–4)^2+(7–3)^2

√1+16

√17

Answer 2

Given, Ratio = 2:3

m1 = 2, m2 = 3

By Section - Formula,

For internally,

x = ( m1x2 + m2x1 ) /( m1 + m2)

x = [ 2(5) + 3( 4) ] /5

x = ( 10 + 12 ) / 5 = 22/5

y = ( m1y2 + m2y1 ) / 5

y = [ 2(7) + 3(3 )] / 5

y = ( 14 + 9 ) /5

y = 23 / 5

For externally,

x' = m1x2 - m2x1 / m1 - m2

x' = - [ 10 - 12] / 1

x' = 2

y' = ( m1y2 - m2y1 ) / ( m1 - m2)

y' = - [ 14 - 9 ] /1

y' = - 5

Distance = $\sqrt{{(x'\:-\:x)} ^{2}\: + \:{(y'\:-\:y)} ^{2}}$

Distance = $\sqrt{{(2\:-\:22/5)} ^{2}\: + \:{(-5\:-\:23/5)} ^{2}}$

Distance = $\sqrt{{(-12/5)}^{2}\: + \:{(-48/5)} ^{2}}$

Distance = $\sqrt{ 144/25 \: + \:2304/25}$

Distance = $\sqrt{ (\:2448\:)/25}$

Distance = 12$\sqrt{17}$/5 units.