Question

please solve the question
and I will make you brainlist​

Answer 1

SOLUTION :-

$\implies$ let assume that, the side of first cube be a and side of second cube be A.

$\rightarrow$ the volume of first cube(a) = a³

$\rightarrow$And Volume of second cube(A) = A³

$\rightarrow$ .°. (a/A)³=a³/A³ = 1/64 = (1)³/(4)³ = (1/4)³

$\rightarrow$ .°. (a/A)³ = (1/4)³

$\implies$ .°. a/ A= 1/4 -----(1)

$\rightarrow$ .°. the area of first cube(a)= 6a²

$\rightarrow$Or area of second cube(A)= 6A²

$\rightarrow$ 6a²/6A²

$\rightarrow$ a²/A²

$\rightarrow$ (1)²/(4)² -----[from equ. (1)]

$\implies$ 1/16

$\implies$ ${\boxed{\boxed{\red{.°. 1:16}}}}$

Hence, the ratio of the area is 1:16.

Answer 2

Here your answer user.