please solve the question and send your answer and gives it a brainlist mark
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As CEIIAB, angle BAC=angle=ACE=angle=80
angleACB +80+35=180
angleACB =180-115°=65°
angleACB +80+35=180
angleACB =180-115°=65°
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here is your answer
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MendatorXI:
plz mark my answer as brain list
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