please solve the question as fast as possible
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HEY MATE!!!
PLZZ REFER THE ATTACHMENT FOR ANSWER
PLZZ REFER THE ATTACHMENT FOR ANSWER
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Given
A right isoceles trianglular field such that AB=BC =20m and Ac =40m
Now
The given field represents a triangle with the above measures...
Area of the field = Area of triangleABC= 1/2*AB*BC
--1/2 *20*20=200
thus the area of the field=200 sq.mt
Again
The perimeter of the field=AB+BC+AC
i.e,20+20+40=80
thus the perimeter =80 m
The cost of fencing the field =perimeter *(cost required to fence 1m)
i.e, 80*70=5600/-
Thus the cost required to fence the field is Rs.5600.
I think this is the answer.
A right isoceles trianglular field such that AB=BC =20m and Ac =40m
Now
The given field represents a triangle with the above measures...
Area of the field = Area of triangleABC= 1/2*AB*BC
--1/2 *20*20=200
thus the area of the field=200 sq.mt
Again
The perimeter of the field=AB+BC+AC
i.e,20+20+40=80
thus the perimeter =80 m
The cost of fencing the field =perimeter *(cost required to fence 1m)
i.e, 80*70=5600/-
Thus the cost required to fence the field is Rs.5600.
I think this is the answer.
atharv1413:
how u did the some can u explain
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