Question

Please solve the question attached

Answer 1

Answer:

c

Step-by-step explanation:

bcz sin theta =opp/hyp

cos theta =adj/hyp

so hyp is same for both according to options answer is c

Answer 2

$\sin(0) = \frac{a}{b} = \frac{perpendiculr}{hypotenuse} \\ let \: base \: be \: c \\ \: {a}^{2} + {c}^{2} = {b}^{2} \\ c = \sqrt{ {b}^{2} - {a}^{2} } \\ \cos(0) = \frac{c}{b} = \frac{\sqrt{ {b}^{2} - {a}^{2} }}{b}$