Math, asked by sanidhyasingla, 1 year ago

please solve the question by showing its explanation

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Answered by Thatsomeone
1
Consider ∆BDA

angle ADB+DBA+BAD=180

angle BAD=26

angle DAC=90-26=64

consider∆EAC

angle DEC is an exterior angle

therefore

angle DEC=angleACE+angleEAC

angle EAC=angle DAC

angle DEC-angle ACE=64

Thatsomeone: thanks for selecting my answer as brainliest
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