Please solve the question
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1
Answer:
ANSWER
In the given figure,
∠C=90
∘
In △ABC,
tan∠ABC=
B
P
=
BC
AC
In △CDB,
tan∠DBC=
B
P
=
BC
CD
Now,
tan∠DBC
tan∠ABC
=
BC
CD
BC
AC
tan∠DBC
tan∠ABC
=
CD
AC
tan∠DBC
tan∠ABC
=
CD
2CD
tan∠DBC
tan∠ABC
=2 (D is mid point of AC)
Answered by
1
answer :
[1]tancab/tancdb= 1/2
[2] tanabc/tandbc = 2
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