Question

please solve the question correctly and I will make him brainliest.​

Answer 1

Answer:

Step-by-step explanation:

In ∆ BDE and ∆ CDF∠BED=∠CFD=90°∠BDE=∠CDF

(Vertically Opposite angles)BD=CD

(Since AD is median of BC)ByAAS congruence ,

∆ BDE≅∆ CDFTherefore,BE=CF (By CPCT)

Hence Proved

Answer 2

Answer:

Step-by-step explanation:

ΔDBE                 ΔDCF                                       Reason

BD              =         DC (Hypotenuse)        AD is the median of ΔABC

∠E              =         ∠F(Right angle)              Both of them are right angles

ED              =         DF (Side)                         BC bisects EF

∴ ΔDBE   ≅   ΔDCF  under the RHS congruence

So,BE = CF (corresponding parts of congruent triangles)