Science, asked by amanmishra94, 1 year ago

please solve the question - electro chemistry​

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Answered by palakdhimam
0
cu is reduced and ag is oxidised... break it into two reaction.. that is oxidation reaction and reduction reaction then.. Emf of cu - Emf of ag
Answered by itsbeasthk
0

Answer:

Cu(s)+2Ag²⁺(aq) ⟶ Cu²⁺(aq)+2Ag(s)

E° = 0.46V at 298K

log K꜀ = nFE° / RT

= 2 x 0.46 / 0.059

K꜀ = 4 x 10¹⁵

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