Chemistry, asked by Harsh5103, 9 months ago

Please solve the question given in attachment.

Attachments:

Answers

Answered by sarwatziazia
1

Answer:

a) lead nitrate salt

b) nitrogen dioxide gas

c) thermal decomposition reaction

d) 2Pb(No^3)2>2PbO+4No2+O2

Answered by Anonymous
1
\Large\underline\mathfrak{Question}

Q. 1 ) A White Colour salt on heating produces a brown gas

a) Identify the salt and write it's chemical name.
b) Identify the name of the gas evolved.
c) Identify the type of chemical reaction.
d) write a balanced chemical equation for the reaction.

\rule{200}{4}

\bold{\boxed{\large{\boxed{\orange{\small{\boxed{\large{\red{\bold{\:ANSWER}}}}}}}}}}

\rule{200}{4}

a) Identification of salt and it's chemical name,

→ White salt producing the brown colour gas.
This indicates the presence of nitrate ion.

→ it may be the salt contains nitrate ion (NO3)-

for example ,

→ it must be lead nitrate " Pb (NO3)2 " if it implies the yellow colourish residue left after heating.

→ Chemical name of salt is

Pb (NO3)2 / or / X No3

\rule{200}{4}

b) identification of gas evolved

→ The production of brown gas indicating that the nitrogen dioxide gas is evolved.

→ But , it may be the another gas

Example → in some chemical reactions bromine ( brown gas ) is produced .

→ The another one with the product must be oxygen ( included in this reaction ) which is colourless but can brightly glow ( Depends upon the quantity of oxygen ) .

\rule{200}{4}

c) identification of reaction's type ,

→ As , we are supposing that this reaction involves the thermal heating / or / breakdown of the nitrate salt / lead nitrate which is given below ,

Pb(NO3)2 ––––––⟩ PbO + NO2 + O2

→ The Decomposition will take place if the temperature is in between 200 - 470 ( °C )

→ it involves thermal decomposition of Lead nitrate Pb(NO3)2.

→ So , it is Decomposition reaction.

\rule{200}{4}

d) Balanced chemical equation for the decomposition of Lead nitrate ,

→ Balanced equation for this reaction is ,

2 Pb(NO3)2 ———— ⟩ 2 PbO + 4 NO2 + O2

\rule{200}{4}

\huge\bold{\red{\ddot{\smile}}}
Similar questions