Question

Please solve the question in a meaning way...
Chapter-Number System
Class 9​

Answer 1

Step-by-step explanation:

$\frac{ {2}^{30} + {2}^{29} + {2}^{28} }{ {2}^{31} + {2}^{30 } - {2}^{29} } \\ = \frac{ {2}^{28} ( {2}^{2} + 2 + 1)}{ {2}^{29}( {2}^{2} + 2 - 1) } \\ = {2}^{28 - 29} \times \frac{4 + 2 + 1}{4 + 2 - 1 } \\ = {2}^{ - 1} \times \frac{7}{5} \\ = \frac{1}{2} \times \frac{7}{5} \\ = \frac{7}{10} \: \: ans.$

Answer 2

Answer:

This is done in RHS & LHS

Hope this helps...