please solve the question in detail
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Step-by-step explanation:
x^3 ax +b+8=0 if divided by x-3
x^3 +ax+b+8=2 if divided by x-2
putting X =3 and x-2 , in above equation...
27+3a+b+8=0....(1)
08+2a+b+8=2....(2)
on subtracting both equation
19+a=-2
a=-2-19
a= -21...
value of b is equal to ...
8-42+b+8=2
b=-26
hope it helps..
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