Math, asked by Anonymous00004, 10 months ago

Please solve the question in the attachment.​

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Answered by Anonymous
4

HEYA \:  \:   \\ find \: -  ( \alpha  -  \beta ) \div  (   \alpha  \beta )\\  \\  for \: a \: general \: quadrati \: equation \: say \:  \\ ax { }^{2}  + bx + c = 0 \\  \\ ( \alpha  +  \beta ) =  - b \div a \\ and \\ ( \alpha  \beta ) = c \div a \\  \\  \\  \\ -  ( \alpha  -  \beta ) \div ( \alpha  \beta ) =  \sqrt{( \alpha  +  \beta ) {}^{2} - 4 \alpha  \beta  }  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \: -  -  -  -  -  -  -  -  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  - ( \alpha  \beta ) \\ \\  \\   - ( \alpha  -  \beta ) \div ( \alpha  \beta ) =  \sqrt{( - 1) {}^{2} - 4( - 2) }  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  -  -  -  -  -  -  -  -  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 2 \\  \\  \\  - ( \alpha  -  \beta ) \div ( \alpha  \beta ) = 3 \div 2

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