Question

Please solve the question in the image.

Answer 1

Answer:

0

Step-by-step explanation:

Tan(Π/11)+Tan(2Π/11)+Tan(3Π/11)+(8Π/11)+Tan(9Π/11)+Tan(10Π/11)=Tan(Π/11)+Tan(2Π/11)+/+Tan(Π-(3Π)/11)+Tan(Π-(2Π)/11)+Tan(Π-(Π)/11)

=Tan(Π/11)+Tan(2Π/11)+Tan(3Π/11)-Tan(Π/11)-Tan(2Π/11)-Tan(3Π/11)

=0

Hence, Tan(Π/11)+Tan(2Π/11)+Tan(3Π/11)+(8Π/11)+Tan(9Π/11)+Tan(10Π/11)=0

I think so in the question it is 8Πbut not 7Π.If it is 7Π then please ignore me