Question

Please solve the question in the image

Answer 1

Answer:

1) Figure A is equable shape.

=> sum of sides = 16.2

=> Area A = 4.5*3.6 = 16.2

Figure B is not equable ahape.

=> Sum of sides = 5+5+6 = 16

=> Area = 1/2 * 6*5 = 15

2) 10 and y = 2.5

=> sum of sides = 2*10 + 2*2.5 = 25

=> Area A = 10*2.5 =25

Answer 2

Answer:

$1figure \: \\ = sum = sides = 16.2 \\ = area \: a \: = 4.5 \: \: 3.6 \: = 16.9 \\ 2 \: figure \: b \\ = sum = 5 + 5 + 6 = 16 \\ = area = 1 | \: 2 \: \: 6 \: \: \: 5 = 15 \\ 2)10 \: and \: y = 2.5 \\ sum \: of \: sides \: = 2.10 + 2.25 = 25 \\ area \: a = 10 \: \: \: 2.5 \: = 25$