Question

please solve the question in the image​

Answer 1

Answer :-

$\sf\huge \dfrac{y - 6}{4} = \dfrac{2y}{5} - \dfrac{7(y + 3)}{20}$

$\sf\longrightarrow \dfrac{y - 6}{4} = \dfrac{2y}{5} - \dfrac{7y + 21}{20}$

$\sf\longrightarrow \dfrac{y - 6}{4} = \dfrac{8y - (7y + 21)}{20}$

$\sf\longrightarrow \dfrac{y - 6}{4} = \dfrac{8y - 7y - 21}{20}$

$\sf\longrightarrow \dfrac{y - 6}{4} = \dfrac{y - 21}{20}$

$\boxed{\sf Cross \: multiplying \: the \: terms}$

$\sf\longrightarrow 20(y - 6) = 4(y - 21)$

$\sf\longrightarrow 20y - 120 = 4y - 84$

$\sf\longrightarrow 20y - 4y = - 84 + 120$

$\sf\longrightarrow 16y = 36$

$\sf\longrightarrow y = \dfrac{36}{16}$

$\boxed{\underline{\sf \therefore y = \dfrac{9}{4}}}$

Answer 2

$\sf{Answer}$

Step by step explanation:-

$\sf\dfrac{y-6}{4}$ = $\sf\dfrac{2y}{5}$ - $\sf\dfrac{7(y+3)}{20}$

$\sf\dfrac{y-6}{4}$ = $\sf\dfrac{2y}{5}$ -$\sf\dfrac{7y+21}{20}$

$\sf\dfrac{y-6}{4}$ = $\sf\dfrac{8y-7(y+3)}{20}$

$\sf\dfrac{y-6}{4}$ = $\sf\dfrac{8y-7y-21}{20}$

$\sf\dfrac{y-6}{4}$ =$\sf\dfrac{y-21}{20}$

$\sf{y-6}$ = $\sf\dfrac{y-21}{5}$

$\sf{Do\:cross\: multiplication}$

$\sf{5(y-6)}$ = $\sf{y-21}$

$\sf{5y-30}$ = $\sf{y-21}$

$\sf{Transpose\: like\:terms}$

$\sf{5y-y=30-21}$

$\sf{4y=9}$

$\sf\dfrac{9}{4}$ = $\sf{y}$

Hope u helpful

Thank u :)