Question

please solve the question no. 8,9 &11​

Answer 1

Answer:

answer is 1π.13is is seen in NCERT book of 12

Answer 2

9) 2x^-1 + x^-1/2 = 6

2/x + 1/√x = 6

2+ √x = 6x

6x - √x -2 = 0

6x - 4√x+ 3√x - 2= 0

2√x( 3√x - 2) + (3√x-2)= 0

2√x+1)( 3√x-2)= 0

2√x = -1 ( which is not possible as both 2 and√x is positive)

3√x= 2

√x= 2/3

x= 4/9

11) √x/( 1- x). + √(1-x)/x = 13/6

x+ 1- x)/ √(x)(1- x). = 13/6

1/√x(1-x). = 13/6

1/x(1- x) = 169/36

36/169 = x( 1- x)

36/169 = x- x^2

36/169 + x^2 - x= 0

169 x^2 - 169 x +36 = 0

169 x^2 -117x -52 x +36= 0

13x( 13x -9) -4( 13x - 9) = 0

( 13x -4)( 13x-9)= 0

x= 4/13, 9/13