please solve the question no.9
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hi
here might be the answer ur searching forrrrr
1.diameter=4.2m.
therefore radius(r)=2.1m.
height(h)=4.5m
C.S.A of a cylinder=2(pi)(r)(h).
=2(22/7)(2.1)(4.5)
=59.4m2.
2.T.S.A=2(pi)(r)(h+r)
=2(22/7)(2.1)(4.5+2.1)
=13.2(6.6).
=87.12m2.
2.Steel used:
Total surface area of the closed cylindrical petrol storage tank
= 2πr (r + h)
= 2×22/7 ×6.6
= 87.12 cm^2
Area of steel sheet wasted in making the tank
= 1/12 × total surface area
= 1/12 × 87.12
7.26
Actual area of the sheet used for making the tank.
= Total surface of the tank + Area of steel sheet wasted in making the tank
= 87.12 m2 + 7.26 m2
= 94.38 m2
here might be the answer ur searching forrrrr
1.diameter=4.2m.
therefore radius(r)=2.1m.
height(h)=4.5m
C.S.A of a cylinder=2(pi)(r)(h).
=2(22/7)(2.1)(4.5)
=59.4m2.
2.T.S.A=2(pi)(r)(h+r)
=2(22/7)(2.1)(4.5+2.1)
=13.2(6.6).
=87.12m2.
2.Steel used:
Total surface area of the closed cylindrical petrol storage tank
= 2πr (r + h)
= 2×22/7 ×6.6
= 87.12 cm^2
Area of steel sheet wasted in making the tank
= 1/12 × total surface area
= 1/12 × 87.12
7.26
Actual area of the sheet used for making the tank.
= Total surface of the tank + Area of steel sheet wasted in making the tank
= 87.12 m2 + 7.26 m2
= 94.38 m2
MukeshPathakrockstar:
But 2nd answer is wrong
hmm but in ncert
same answer is there
say the answer
No, the answer in ncert is 95.04m square
just points difference na
there is a differenceof 0.66m square
is the process correct
no
hmm
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