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Answered by
2
Answer:
thin pipe
Explanation:
Let F be the force acting on a body . Let O be the centre of body.
Now lets search for , value of distance between line of action of and centre of body so that body starts slip from rolling.(say "x")
F=ma {Newton's law of motion}------->1
Fx=Iα------------>2
by solving those two we get,
x=mrI.
since ,
I=32mr2 for thin spherical shell;
I=52mr2 for solid spherical shell;
I=21mr2 for solid cylinder;
I=mr2 for thin pipe.
by substituting,
only thin pipe satisfies the above condition of rolling if force is applied on the top of body.
Answered by
5
Answer:
thin pipe
Explanation:
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