Question

please solve the question.....

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Answer 1

Answer:

k=2

Step-by-step explanation:

given (px) =x³-3kx²-x+30

and Sum of zeroes =6

we know that sum of zeroes=-b/a

therefore

-b/a=6

3k/1=6. (-b=3k and a=1)

k=2

hence k=2

hope this helps you

Answer 2

AnsWer :

2.

Given :

• f(x) = x³ -3kx² -x +30.
• Sum of zeros be 6.

To Find :

The value of k

Solution :

We have polynomial f(x),

$\tt \big \langle \langle \: \: \: \: {x}^{3} - 3 {x}^{2} - x + 30.$

We know,

$\tt \blacksquare sum \: of \: zeros. \\ \tt \alpha + \beta + \gamma = \frac{ - b}{a} = \frac{coefficient \: of \: {x}^{2} }{coefficient \: of \: {x}^{3} }$

$\rule{90}1$

We have already the value of,

$\tt\dagger \: \: \: \alpha + \beta + \gamma = 6.$

$\tt \longmapsto \alpha + \beta + \gamma = \frac{ - b}{a}$

$\tt \longmapsto 6 = \frac{ - ( - 3k)}{1}$

$\tt \longmapsto 6 = 3k.$

$\tt\longmapsto k = \frac{ \cancel6}{ \cancel3}$

$\tt\longmapsto k = 2.$

Therefore,the value of k be 2.