please solve the question number 1 ka A and B very urgent and c
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sum of all interior angles of a quadrilateral is 360°
so angle S=360-255=105°
in the next question let the ratio be 4x:5x:5x:6x
4x+5x+5x+6x=360
x=360/20=18
so the angles are 4x=72
5x=90
5x=90
6x=108
so angle S=360-255=105°
in the next question let the ratio be 4x:5x:5x:6x
4x+5x+5x+6x=360
x=360/20=18
so the angles are 4x=72
5x=90
5x=90
6x=108
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