please solve the question number 15 and answer them
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In triangle ABC
angle ABC+ angle BCA+ angeCAB= 180°. [angle sum property]
In triangle ACD
angleACD+ angleCDA+ angle DAC=180°. [ angle sum property]
In triangle ADE
angle ADE + angleDEA + angleEAD= 180° [angle sum property]
By adding the three equations
angle A BC+ angleBCA + angleCAB+ angleACD + angle CAD + angleDAC + angleADE+ angleDEA+ angleEAD=180°+180°+180°
therefore
angle A BC+ angleBCD + angleCDE+ angle DEA+ angleEAB=540°
Explanation for angle sum property:
Angle sum property of triangle states that the sum of interior angles of a triangle is 180°.
OR
the formulae for finding the sum of all angles of a figure is 180(n-2) where n is the number of sides
therefore sum of all sides=180(5-2)=180*3=540°
Hope it helps
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