please solve the question number 2,3 with solutions in a copy
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ayankhan51:
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3 .
In isosceles triangle ABC -
AB=6 cm
AC=6cm
but side BC is the diameter of circle
therefore, radius = diameter /2
108/20 =27/5
Radius =27/5
circumference of circle =2pie r(sq)
Half circumference =2pie r(sq)/2
2 is cut down we get
22/7multiply with 27/5=594/35
=16.97.....
perimeter of whole figure =side BA+AC+length of half circumference
6+6+16.97
=28.97 cm ( approx)
In isosceles triangle ABC -
AB=6 cm
AC=6cm
but side BC is the diameter of circle
therefore, radius = diameter /2
108/20 =27/5
Radius =27/5
circumference of circle =2pie r(sq)
Half circumference =2pie r(sq)/2
2 is cut down we get
22/7multiply with 27/5=594/35
=16.97.....
perimeter of whole figure =side BA+AC+length of half circumference
6+6+16.97
=28.97 cm ( approx)
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