please solve the question number 8 and 9 send a pic of the solution
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Q8) the acute angles of a right angled triangle are 1x and 4x. ( Let the common ratio be x).
1x+4x+90 = 180 (angle sum property)
= 5x +90 = 180
= 5x = 90
= x = 90/5
= x = 18
The acute angles are 1×18= 18°
And 4×18= 72°
Q9) let common ratio be x.
Angles are 2x and 3x
2x + 3x + 105 = 180 ( angle sum property)
= 5x +105 = 180
= 5x = 75
= x = 75/5
= x = 15
Hence the angles are:
2 × 15= 30°
3 × 15= 45°
Please mark it brainliest answer please plzzzz
1x+4x+90 = 180 (angle sum property)
= 5x +90 = 180
= 5x = 90
= x = 90/5
= x = 18
The acute angles are 1×18= 18°
And 4×18= 72°
Q9) let common ratio be x.
Angles are 2x and 3x
2x + 3x + 105 = 180 ( angle sum property)
= 5x +105 = 180
= 5x = 75
= x = 75/5
= x = 15
Hence the angles are:
2 × 15= 30°
3 × 15= 45°
Please mark it brainliest answer please plzzzz
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