Math, asked by nancyjoon028, 7 months ago

please solve the question quickly​

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Answered by ItzNoName
0

Answer:

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Answered by CoruscatingGarçon
19

Answer:

 \frac {1}{a}

Step-by-step explanation:

=>  \frac {a^{7+2n} * a^{2(3n+2)}} {a^{4(2n+3)}}

=>  \frac {a^{7+2n} * a^{6n+4}} {a^{8n+12}}

=>  a^{7+2n+6n+4-8n-12}

=>  a^{-1+0n}

=>  \frac {1}{a}

HOPE IT HELPS!!!

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