Please solve the question shown in this image.
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Answer:
These resistence are connected in series
R1+R2+R3=RS
=5.6+3.3+2.2
=. 11. 1Kohm
=11100ohm
Vs=V1+V2+V3
=10+20+30
=60V
I=V/R
=60/11100
=6/1110
=0.005A
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