Physics, asked by saras88, 9 months ago

Please solve the question shown in this image.​

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Answered by habishajahan93
0

Answer:

These resistence are connected in series

R1+R2+R3=RS

=5.6+3.3+2.2

=. 11. 1Kohm

=11100ohm

Vs=V1+V2+V3

=10+20+30

=60V

I=V/R

=60/11100

=6/1110

=0.005A

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