Physics, asked by avanishtiwari11, 9 months ago

please solve the question step by step​

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Answered by lahukhairnar
2

Answer:

hsin^2 theta

the vertical speed at bottom is given by

u=√2gh sin

no the max hight is given by

y=u^2/2g

=2gh sin^2/2g

=h sin^2 theta

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